**
Field Theory - Online Tutorial 2 **

**by Kevin Tang ,
last update: Apr 27, 2014, 2:00PM**

__ELE401 Final Exam Review Notes__ (My own note, it have some important formulas
that you should know for your final exam) [**3.65MB**]
.. [ Download Here ]

A Letter From Kevin :D

To everyone, my friends, its my pleasure to have this chance to work with you and help you at some point this semester, very sorry, because I am very busy with my research work, >_< therefore, I won't able to provide another actual tutorial before Monday, but I will upload as many notes as possible, few key things I wish to said for this exam based on my own experience.
FIRST: as always, just like I said, try to cover the topic AS WIDE AS POSSIBLE, yet, FIRST, YOU MUST able to solve ALL THE BASIC PROBLEMS, such as "Biot-Savart Law", "Gaussian surface" questions...etc BUT also like on midterm, many people forget or mixed up the equation for energy density, many of you told me that is a SMALL part in the text book, and that is true, usually those are the place set the different between A and A-.
SECOND: Are you able to write down all the important formula without any hint? If not, you are not ready. than, this is usually my study guide, (1) able to solve ALL the example in the TEXT BOOK, and understand WHY and HOW. <-- Start here (2) able to solve ALL the example taught in the CLASS without looking at the solution. (3) able to solve ALL the example taught in the TUTORIAL without looking at any solution (4) solve all the ASSIGNED QUESTION (focus on the part AFTER MIDTERM!) (5) Finished (1) to (4), maybe you can close your eye and...
RANDOMLY ask your self any question, for example, Biot–Savart law question, V and able to get from beginning to end HOW TO SOLVE IT, what is the first step to the end.
THIRD: Some of my fourth year student said this course is "failed theory", at this point, I won't said this is an easy course, but I can tell you the truth everyone who failed or get lower than B is because they are lazy and don't want study, I know many people get higher than A- in the end, not because any other reason, because they STUDY SPEND the TIME NOW, from NOW TILL MONDAY, you have time, get with your friend, ask your buddy, SPEND ALL YOUR TIME AND ENERGY HERE AND NOW, you can play later, you have all the time this summer, in the end, A+ will be yours
Good Luck!!! I wish you all the very best
Best Regards, Kevin Tang
Apr 25, 2014 |

A infinite filaments is placed on x-axis. (as shown in Figure #1). It carries current I = 2[A] in negative x-direction.

a) Find the magnetic field intensity
vector **a _{Φ}** at (3, 4, 0).

Figure #1

Choice one of the following answer. (Solving Time: 1 min)

A | B | C | D |

__SOLUTION 1a)__

How to find it?

Simply perform the cross product between the current direction and direct direction.

That is −a_{x} (current
direction **a_{l}**) × a

**a _{Φ}** =

both **a_{l}**
and

**−a _{z
= }−a_{x}
× a_{y }**

Another way you can find direction as following...

First, put your RIGHT HAND (in case if you don't know which hand is right hand, its the opposite side to your heart *for most people) on

the CURRENT LINE, point your RIGHT HAND THUMB at same direction as the CURRENT GOES

(shown in *Figure #2*)

*Figure # 2*

Now, ROTATE as your hand goes, this is your FLUX DIRECTON

as you can see, if you looking from positive X direction toward negative X direction, it is CLOCKWISE

when the FLUX hit the our TARGET POINT (3, 4, 0), its PUSH DOWN toward negative
Z (**−a _{z}**)direction

*Figure # 3*

Looking to the Z-Y Plane, you can see it more clear. (shown in __ Figure #4__)

* Figure # 4*

*Important Notice, some case (most case), don't forget the
step for **unit vector**,

our case it cancel out, because √ (3^{2}+ 0^{2})
= 3 , where 3/3 = 1.

**1b)** Now, find **H**
at (3, 4, 0), same graph

Maximum Solving Time : 3 min

A |
B |
C |
D |

__SOLUTION 1b)__

What is the equation for the line current affect on a single point?

The following equation you need to know ... (**eq.1**)

... **eq.1**

Where, θ_{1} and θ_{2} are located as following. (shown in *
Figure 5*)

__ Figure #5__

Now, when we have an infinite line, where θ_{1} will be approach 180^{o}
and θ_{2} will approach 0^{o }(shown in *Figure #6*)

*Figure # 6*

Put everything in, you have the equation for Infinite Line (shown in Figure #7)

Figure #7

With this, your last step is just put everything in,

notice, your **ρ** is the shortest distance from your line (extend parallel) to your
point.

In our case, its equal to 4 (shown in *Figure #8*)

*Figure #8*

Now, you get the final answer -- which is B.

**1c)** - Given μ = μ_{o},
please find **B** at (3, 4, 0), same graph

Maximum solving time: 1 min

A |
B |
C |
D |

This should be very simple, the relation between **B** and **H** is as
following...

(the way I think, they are brothers or sisters, **B** is brother for **H**,
as well as **D** is brother for **E**)

Just multiply it by the constant μ_{o},.. than you get your
answer..

The only thing some people may forget is the UNIT for the B, its "Tesla" (T)

So the answer is D, very easy right? lol

* Note: also, T = Wb/m^{2}

**Q2 -**

Find the work to move the conductor with current *I* flow in positive **a _{z}**
direction,

of the length L_{1}, the conductor is been placed
vertically upward at (c, 0, 0),

for one full
revolution about the z-axis if the magnetic flux density **B** = B_{0}ρ**a _{ρ}**.

the revolution shape is a circular shape with radius r = c [m].

.

**SOLUTION 2)**

d**F** = *I*d**l** × **B**

where d**l** = dz**a _{z}**

(notice this d**l **is the conductor line, with length
L_{1})

*I*d**l** × **B** = *I* (dz**a _{z}** × B

_{
}= *I*_{ }B_{0}ρa_{Φ}

notice ... **a _{z}** ×

d**F** = *I* B_{0}ρdz a_{Φ}

than, take integral on both side...

**F** = ∫_{0}^{L }*I *B_{0}ρdz a_{Φ}

= L_{1}*I*B_{0}ρ c a** _{Φ}**
[N]

After you find the force, than

dW = **F** · d**l**

where d**l **= ρdΦ**a _{Φ}**

(This d**l** is respect to the "one full revolution")

dW = (L_{1}*I *B_{0}ρ c a** _{Φ}**) · (ρdΦ

= L_{1}*I *B_{0} c^{2}
dΦ ... where ρ = c

W = ∫_{0}^{2π }L_{1}*I *B_{0} c^{2}
dΦ

= 2π L_{1}*I *B_{0} c^{2 }[J]

ANSWER: W = 2π L_{1}B_{0}ρ c^{2
}[J]

__ Q3 -__ Bio-savart Law question

Base on George's request, this is our question lol

Find **H** at origin (0, 0, 0), given 2 current line,

Line 1: z = y + 1 (−∞ < y < ∞), current = 2[A] is flowing from negative y direction toward positive y direction.

Line 2 : z = 2y − 4 (0 __<__ y __<__ 2),
current = 1[A] is flowing from positive y direction toward negative y direction.

a) Draw the diagram

b) Find **H _{1}**

c) Find **H _{2}**

d) Find **H**

__SOLUTION Q3)__

To find the **H**, we can split into **H** = **H _{1}** +

First, draw the diagram, you can see the line relationship are all between y and z, so its y-z plan

So, we start with **H _{1}**,

looking at line 1 respect to the origin point, use RIGHT HAND RULE, you can see
its going toward NEGATIVE X (**-a _{x}**) DIRECTION,

well, the only issue is you won't able to find the unit vector using right hand rule (but you can use it to check the answer)

the same thing you can applied using equation **a _{Φ}** =

where **a_{l}** is the direction of the current flowing

where **a _{ρ}** is the direction from the LINE to the TARGET
POINT

**ρ **is the shortest distance to the extend line (if line is finite,
extend the line all the way,
**ρ** will be the shortest distance of this extend line to the point)

Than, you got your **H _{1}**...

Next, find H2

Last step... Just add up **H _{1}** and

**H** = **H _{1}** +

*Notice, on the exam, it could be a circular current line instead of straight line...

nothing really change, just use the same concept as you start with

** a _{Φ}** =

so you cross it, got the result, ... just think more before you start any question

* Question for F (force) and T (torque)

You may leave me any message if you have any questions, I will try to answer ASAP, thanks and good luck :)